SATHEE: Electrostatics Question 160

Electrostatics Question 160

Question: $F_{g}$ and $F_{e}$ represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of $F_{g} / F_{e}$ is of the order of [NCERT 1978; CPMT 1978]

Options:

A) $10^{42}$

B) 10

C) 1

D) $10^{- 43}$

Show Answer

Answer:

Correct Answer: D

Solution:

Gravitational force between electrons $F_{G} = \frac{G {(m_{e})}^{2}}{r^{2}}$

Electrostatics force between electrons $F_{e} = k . \frac{e^{2}}{r^{2}}$

$\frac{F_{G}}{F_{e}} = \frac{G {(m_{e})}^{2}}{k . e^{2}} = \frac{6.67 \times 10^{- 11} \times {(9.1 \times 10^{- 31})}^{2}}{9 \times 10^{9} \times {(1.6 \times 10^{- 19})}^{2}}$

$= 2.39 \times 10^{- 43}$

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Electrostatics Question 160

Question: Fg and Fe represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of Fg/Fe is of the order of [NCERT 1978; CPMT 1978]

Options:

Answer:

Solution:

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Question: $F_{g}$ and $F_{e}$ represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of $F_{g} / F_{e}$ is of the order of [NCERT 1978; CPMT 1978]