Electrostatics Question 154
Question: The potentials of the two plates of capacitor are +10V and ?10 V. The charge on one of the plates is 40 C. The capacitance of the capacitor is [AFMC 2005]
Options:
A) 2 F
B) 4 F
C) 0.5 F
D) 0.25 F
Show Answer
Answer:
Correct Answer: A
Solution:
The potential difference across the parallel plate capacitor is $ 10V-(-10V)=20V. $
Capacitance $ =\frac{Q}{V}=\frac{40}{20}=2F. $
