Electrostatics Question 132
Question: The unit of electric permittivity is [MP PET 2003]
Options:
A) $ Volt/m^{2} $
B) Joule/coulomb
C) Farad/m
D) Henry/m
Show Answer
Answer:
Correct Answer: C
Solution:
$ C=\frac{{\varepsilon _{0}}A}{d} $
therefore $ {\varepsilon _{0}}=\frac{Cd}{A} $
therefore $ {\varepsilon _{0}} $ ® $ \frac{Farad\times m}{m^{2}}\to \frac{F}{m} $
