SATHEE: Electrostatics Question 102

Electrostatics Question 102

Question: The capacity of a parallel plate condenser is $15 μ F$ , when the distance between its plates is 6 cm. If the distance between the plates is reduced to 2 cm, then the capacity of this parallel plate condenser will be [AFMC 2000]

Options:

A) $15 μ F$

B) $30 μ F$

C) $45 μ F$

D) $60 μ F$

Show Answer

Answer:

Correct Answer: C

Solution:

$C \propto \frac{1}{d} \Rightarrow$

$\frac{C_{1}}{C_{2}} = \frac{d_{2}}{d_{1}}$

therefore $\frac{15}{C_{2}} = \frac{2}{6}$

therefore C2 = 45mF

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Electrostatics Question 102

Question: The capacity of a parallel plate condenser is 15μF , when the distance between its plates is 6 cm. If the distance between the plates is reduced to 2 cm, then the capacity of this parallel plate condenser will be [AFMC 2000]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

Question: The capacity of a parallel plate condenser is $15 μ F$ , when the distance between its plates is 6 cm. If the distance between the plates is reduced to 2 cm, then the capacity of this parallel plate condenser will be [AFMC 2000]