Electrostatics Question 10

Question: Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is [MP PET 1990; MNR 1987; MP PMT 2002, 03; Pb. PET 2004; J & K CET 2005]

Options:

A) 8 times

B) 4 times

C) 2 times

D) 32 times

Show Answer

Answer:

Correct Answer: C

Solution:

Volume of 8 small drops = Volume of big drop $ 8\times \frac{4}{3}\pi r^{3}=\frac{4}{3}\pi R^{3} $

therefore R = 2r As capacity is r, hence capacity becomes 2 times.



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