Electro Magnetic Induction And Alternating Currents Question 89

Question: The r.m.s. value of an ac of 50 Hz is 10 amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be [MP PET 1993; KCET 2003]

Options:

A) 2 ´ 10?2 sec and 14.14 amp

B) 1 ´ 10?2 sec and 7.07 amp

C) 5 ´ 10?3 sec and 7.07 amp

D) 5 ´ 10?3 sec and 14.14 amp

Show Answer

Answer:

Correct Answer: D

Solution:

Time taken by the current to reach the maximum value $ t=\frac{T}{4}=\frac{1}{4\nu }=\frac{1}{4\times 50}=5\times {{10}^{-3}}sec $ and $ i_{o}=i_{rms}\sqrt{2}=10\sqrt{2}=14.14 $ amp



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