Electro Magnetic Induction And Alternating Currents Question 74

Question: In a circuit $ L,,C\text{ and }R $ are connected in series with an alternating voltage source of frequency $ f $ . The current leads the voltage by 45°. The value of $ C $ is [CBSE PMT 2005]

Options:

A) $ \frac{1}{2\pi f(2\pi fL+R)} $

B) $ \frac{1}{\pi f(2\pi fL+R)} $

C) $ \frac{1}{2\pi f(2\pi fL-R)} $

D) $ \frac{1}{\pi f(2\pi fL-R)} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ \tan \varphi =\frac{X_{C}-X_{L}}{R} $

Þ $ \tan 45^{o}=\frac{\frac{1}{2\pi fC}-2\pi fL}{R} $

Þ $ C=\frac{1}{2\pi ,f(2\pi fL+R)} $



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