SATHEE: Electro Magnetic Induction And Alternating Currents Question 74

Electro Magnetic Induction And Alternating Currents Question 74

Question: In a circuit $L,, C and R$ are connected in series with an alternating voltage source of frequency $f$ . The current leads the voltage by 45°. The value of $C$ is [CBSE PMT 2005]

Options:

A) $\frac{1}{2 π f (2 π f L + R)}$

B) $\frac{1}{π f (2 π f L + R)}$

C) $\frac{1}{2 π f (2 π f L - R)}$

D) $\frac{1}{π f (2 π f L - R)}$

Show Answer

Answer:

Correct Answer: A

Solution:

$\tan φ = \frac{X_{C} - X_{L}}{R}$

Þ $\tan 45^{o} = \frac{\frac{1}{2 π f C} - 2 π f L}{R}$

Þ $C = \frac{1}{2 π, f (2 π f L + R)}$

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Electro Magnetic Induction And Alternating Currents Question 74

Question: In a circuit L,,C and R are connected in series with an alternating voltage source of frequency f . The current leads the voltage by 45°. The value of C is [CBSE PMT 2005]

Options:

Answer:

Solution:

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Question: In a circuit $L,, C and R$ are connected in series with an alternating voltage source of frequency $f$ . The current leads the voltage by 45°. The value of $C$ is [CBSE PMT 2005]