Electro Magnetic Induction And Alternating Currents Question 64
Question: A circuit has a resistance of $ 11\Omega , $ an inductive reactance of $ 25\Omega $ and a capacitative resistance of $ 18\Omega . $ It is connected to an ac source of 260V and 50Hz. The current through the circuit (in amperes) is [Kerala PMT 2002]
Options:
A) 11
B) 15
C) 18
D) 20
Show Answer
Answer:
Correct Answer: D
Solution:
$ Z=\sqrt{R^{2}+{{(X_{L}-X_{C})}^{2}}}=\sqrt{{{(11)}^{2}}+{{(25-18)}^{2}}}=13,\Omega $ Current $ i=\frac{260}{13}=20,A $
