Electro Magnetic Induction And Alternating Currents Question 6

Question: A resonant ac circuit contains a capacitor of capacitance $ {{10}^{-6}}F $ and an inductor of $ {{10}^{-4}}H. $ The frequency of electrical oscillations will be

Options:

A) $ 10^{5},Hz $

B) 10 Hz

C) $ \frac{10^{5}}{2\pi }Hz $

D) $ \frac{10}{2\pi }Hz $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \nu =\frac{1}{2\pi \sqrt{LC}}=\frac{1}{2\pi \sqrt{{{10}^{-6}}\times {{10}^{-4}}}}=\frac{10^{5}}{2\pi }Hz $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक