Electro Magnetic Induction And Alternating Currents Question 588

Question: The current in a coil of inductance 5 H decreases at the rate of 2 A/s. The induced e.m.f. is [MH CET 2002]

Options:

A) 2 V

B) 5 V

C) 10 V

D) - 10 V

Show Answer

Answer:

Correct Answer: C

Solution:

$ e=-L\frac{di}{dt} $ , since current decreases so $ \frac{di}{dt} $ is negative, hence $ e=-5\times ( -2 )=+10V $



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