Electro Magnetic Induction And Alternating Currents Question 588
Question: The current in a coil of inductance 5 H decreases at the rate of 2 A/s. The induced e.m.f. is [MH CET 2002]
Options:
A) 2 V
B) 5 V
C) 10 V
D) - 10 V
Show Answer
Answer:
Correct Answer: C
Solution:
$ e=-L\frac{di}{dt} $ , since current decreases so $ \frac{di}{dt} $ is negative, hence $ e=-5\times ( -2 )=+10V $
