Electro Magnetic Induction And Alternating Currents Question 58
Question: A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second ac circuit. The impedance of this combination is very nearly [MP PET 2000]
Options:
A) 30 ohm
B) 40 ohm
C) 50 ohm
D) 60 ohm
Show Answer
Answer:
Correct Answer: C
Solution:
$ Z=\sqrt{R^{2}+{{(2\pi \nu L)}^{2}}} $ $ =\sqrt{{{(40)}^{2}}+4{{\pi }^{2}}\times {{(50)}^{2}}\times {{(95.5\times {{10}^{-3}})}^{2}}}=50ohm $