SATHEE: Electro Magnetic Induction And Alternating Currents Question 574

Electro Magnetic Induction And Alternating Currents Question 574

Question: If in a coil rate of change of area is 5 m2/milli second and current become 1 amp from 2 amp in $2 \times 10^{- 3}, s e c .$ If magnitude of field is 1 tesla then self inductance of the coil is [RPET 2000]

Options:

A) 2 H

B) 5 H

C) 20 H

D) 10 H

Show Answer

Answer:

Correct Answer: D

Solution:

$N φ = L i \Rightarrow \frac{N d φ}{d t} = \frac{L d i}{d t} \Rightarrow N B \frac{d A}{d t} = \frac{L d i}{d t}$
$\Rightarrow \frac{1 \times 1 \times 5}{10^{- 3}} = L \times (\frac{2 - 1}{2 \times 10^{- 3}}) \Rightarrow L = 10 H$

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Electro Magnetic Induction And Alternating Currents Question 574

Question: If in a coil rate of change of area is 5 m2/milli second and current become 1 amp from 2 amp in 2×10−3,sec. If magnitude of field is 1 tesla then self inductance of the coil is [RPET 2000]

Options:

Answer:

Solution:

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Question: If in a coil rate of change of area is 5 m2/milli second and current become 1 amp from 2 amp in $2 \times 10^{- 3}, s e c .$ If magnitude of field is 1 tesla then self inductance of the coil is [RPET 2000]