Electro Magnetic Induction And Alternating Currents Question 560

Question: If the current is halved in a coil, then the energy stored is how much times the previous value [CPMT 1999]

Options:

A) $ \frac{1}{2} $

B) $ \frac{1}{4} $

C) 2

D) 4

Show Answer

Answer:

Correct Answer: B

Solution:

$ U=\frac{1}{2}Li^{2}\ i.e.\frac{U_{2}}{U_{1}}={{( \frac{i_{2}}{i_{1}} )}^{2}}={{( \frac{1}{2} )}^{2}}=\frac{1}{4} $
$ \Rightarrow U_{2}=\frac{1}{4}U_{1} $



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