Electro Magnetic Induction And Alternating Currents Question 555
Question: A coil of self-inductance 50 henry is joined to the terminals of a battery of e.m.f. 2 volts through a resistance of 10 ohm and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to 1/e of its steady value is [MP PMT 1996]
Options:
A) 500 seconds
B) 50 seconds
C) 5 seconds
D) 0.5 seconds
Show Answer
Answer:
Correct Answer: C
Solution:
Time in which the current will decay to $ \frac{1}{e} $ of its steady value is $ t=\tau =\frac{L}{R}=\frac{50}{10}=5 $ seconds
