SATHEE: Electro Magnetic Induction And Alternating Currents Question 526

Electro Magnetic Induction And Alternating Currents Question 526

Question: Two coils of self-inductance $L_{1}$ and $L_{2}$ are placed closer to each other so that total flux in one coil is completely linked with other. If $M$ is mutual inductance between them, then [DCE 2002]

Options:

A) $M = L_{1} L_{2}$

B) $M = L_{1} / L_{2}$

C) $M = \sqrt{L_{1} L_{2}}$

D) $M = {(L_{1} L_{2})}^{2}$

Show Answer

Answer:

Correct Answer: C

Solution:

$M = - \frac{e_{2}}{d i_{1} / d t} = - \frac{e_{1}}{d i_{2} / d t}$

Also $e_{1} = - L_{1} \frac{d i_{1}}{d t} . e_{2} = - L_{2} \frac{d i_{2}}{d t}$ $M^{2} = \frac{e_{1} e_{2}}{(\frac{d i_{1}}{d t}) (\frac{d i_{2}}{d t})} = L_{1} L_{2} \Rightarrow M = \sqrt{L_{1} L_{2}}$

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Electro Magnetic Induction And Alternating Currents Question 526

Question: Two coils of self-inductance L1 and L2 are placed closer to each other so that total flux in one coil is completely linked with other. If M is mutual inductance between them, then [DCE 2002]

Options:

Answer:

Solution:

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Question: Two coils of self-inductance $L_{1}$ and $L_{2}$ are placed closer to each other so that total flux in one coil is completely linked with other. If $M$ is mutual inductance between them, then [DCE 2002]