SATHEE: Electro Magnetic Induction And Alternating Currents Question 484

Electro Magnetic Induction And Alternating Currents Question 484

Question: A conducting square frame of side’ a’ and a long staight wire carrying current I are located in the same plane as . The frame moves to the right with a constant velocity ?V?. The emf induced in the frame will be proportional to

Options:

A) $\frac{1}{{(2 x - a)}^{2}}$

B) $\frac{1}{{(2 x + a)}^{2}}$

C) $\frac{1}{(2 x - a) (2 x + a)}$

D) $\frac{1}{x^{2}}$

Show Answer

Answer:

Correct Answer: C

Solution:

Emf induced in side 1 of frame $e_{1} = B_{1} V ℓ$

$B_{1} = \frac{μ_{0} I}{2 π (x - a / 2)}$

Emf induced in side 2 of frame $e_{2} = B_{2} V ℓ$

$B_{2} = \frac{μ_{0} I}{2 π (x + a / 2)}$

Emf induced in square frame $e = B_{1} V ℓ = B_{2} V ℓ$

$= \frac{μ_{0} I}{2 π (x - a / 2)} ℓ v - \frac{μ_{0} I}{2 π (x + a / 2)} ℓ v$ or,

$e \propto \frac{1}{(2 x - a) (2 x + a)}$

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Electro Magnetic Induction And Alternating Currents Question 484

Question: A conducting square frame of side’ a’ and a long staight wire carrying current I are located in the same plane as . The frame moves to the right with a constant velocity ?V?. The emf induced in the frame will be proportional to

Options:

Answer:

Solution:

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