Electro Magnetic Induction And Alternating Currents Question 459

Question: A square loop with 2.0 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field is . The loop contains a 20.0 V battery with negligible internal resistance. If the magnitude of the field varies with time according to B = 0.042-0.871, with B in tesia and t in second. The net emf of the circuit is:

Options:

A) 20.0,V

B) 18.26,V

C) 21.74,V

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

  • Induced emf. |.e|.=dϕdt=A(dBdt)

    =2×22×ddt(0.0420.87t)=2×0.87=1.74V

    The net induced emf =20+1.74=21.74,V



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