Electro Magnetic Induction And Alternating Currents Question 459

Question: A square loop with 2.0 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field is . The loop contains a 20.0 V battery with negligible internal resistance. If the magnitude of the field varies with time according to B = 0.042-0.871, with B in tesia and t in second. The net emf of the circuit is:

Options:

A) $ 20.0,V $

B) $ 18.26,V $

C) $ 21.74,V $

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

  • Induced emf. $ | . e | .=\frac{d\phi }{dt}=A( \frac{dB}{dt} ) $

    $ =\frac{2\times 2}{2}\times \frac{d}{dt}(0.042-0.87t)=2\times 0.87=1.74V $

    The net induced emf $ =20+1.74=21.74,V $



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