Electro Magnetic Induction And Alternating Currents Question 445

Question: The magnitude of the earth’s magnetic field at a place is B0 and the angle of dip is δ . A horizontal conductor of length l lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is [Kerala PET 2005]

Options:

A) Zero

B) B0l,vsinδ

C) B0l,v

D) B0l,vcosδ

Show Answer

Answer:

Correct Answer: B

Solution:

When a conductor lying along the magnetic north-south, moves eastwards it will cut vertical component of B0 . So induced emf e=vBVl =v(B0sinδ,l) =B0l,vsinδ .



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