SATHEE: Electro Magnetic Induction And Alternating Currents Question 428

Electro Magnetic Induction And Alternating Currents Question 428

Question: A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth’s magnetic field is $0.2 \times 10^{- 4} T$ , then the e.m.f. developed between the two ends of the conductor is [MP PMT 1992; AIEEE 2004]

Options:

A) $5 m V$

B) $5 \times 10^{- 4} V$

C) $50 m V$

D) $50 μ V$

Show Answer

Answer:

Correct Answer: D

Solution:

$e = \frac{1}{2} B ω r^{2} = \frac{1}{2} \times 0.2 \times 10^{- 4} \times 5 \times {(1)}^{2} = 50 μ V$

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Electro Magnetic Induction And Alternating Currents Question 428

Question: A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth’s magnetic field is 0.2×10−4T , then the e.m.f. developed between the two ends of the conductor is [MP PMT 1992; AIEEE 2004]

Options:

Answer:

Solution:

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