Electro Magnetic Induction And Alternating Currents Question 424
Question: A conductor of 3 m in length is moving perpendicularly to magnetic field of $ {{10}^{-3}} $ tesla with the speed of $ 10^{2}m/s $ , then the e.m.f. produced across the ends of conductor will be [MP PET 1990]
Options:
A) 0.03 volt
B) 0.3 volt
C) $ 3\times {{10}^{-3}}volt $
D) 3 volt
Show Answer
Answer:
Correct Answer: B
Solution:
$ e=Bvl=3\times {{10}^{-3}}\times 10^{2}=0.3\ volt $
