Electro Magnetic Induction And Alternating Currents Question 412

Question: In an AC circuit, the voltage applied is $ E=E_{0}\sin \omega t $ . The resulting current in the circuit is $ I=I_{0}\sin (\omega t-\pi /2) $ . The power consumption in the circuit is given by

Options:

A) $ P=0 $

B) $ P=\frac{E_{0}I_{0}}{2} $

C) $ P=\sqrt{2} $ $ E_{0}I_{0} $

D) $ P=\frac{E_{0}I_{0}}{\sqrt{2}} $

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ P_{av}=E_{V}I_{V}\cos \phi $ Here $ \phi = $ phase difference $ =\frac{\pi }{2} $
    $ \therefore P_{av}=0 $


जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक