SATHEE: Electro Magnetic Induction And Alternating Currents Question 397

Electro Magnetic Induction And Alternating Currents Question 397

Question: The magnetic flux linked with coil, in weber is given by the equation, $φ = 5 t^{2} + 3 t + 16$ . The induced emf in the coil in the fourth second is [Pb. PMT 2004]

Options:

A) 10 V

B) 30 V

C) 45 V

D) 90 V

Show Answer

Answer:

Correct Answer: A

Solution:

$| e |, = \frac{d φ}{d t} = \frac{d}{d t} (5 t^{2} + 3 t + 16) = (10 t + 3)$

when $t = 3 \sec, e_{3} = (10 \times 3 + 3) = 33 V$

when $t = 4 \sec, e_{4} = (10 \times 4 + 3) = 43 V$

Hence emf induced in fourth second $= e_{4} - e_{3} = 43 - 33 = 10 V$

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Electro Magnetic Induction And Alternating Currents Question 397

Question: The magnetic flux linked with coil, in weber is given by the equation, φ=5t2+3t+16 . The induced emf in the coil in the fourth second is [Pb. PMT 2004]

Options:

Answer:

Solution:

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Question: The magnetic flux linked with coil, in weber is given by the equation, $φ = 5 t^{2} + 3 t + 16$ . The induced emf in the coil in the fourth second is [Pb. PMT 2004]