Electro Magnetic Induction And Alternating Currents Question 343
Question: A conducting rod AC of length 4l is rotated about a point O in a uniform magnetic field $ \vec{B} $ directed into the paper. AO = l and OC = 3l. Then
Options:
A) $ V _{A}-V _{O}=\frac{B\omega l^{2}}{2} $
B) $ V _{O}-V _{C}=\frac{7}{2}B\omega l^{2} $
C) $ V _{A}-V _{C}=4B\omega l^{2} $
D) $ V _{C}-V _{O}=\frac{9}{2}B\omega l^{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
By using
$ e=\frac{1}{2}Bl^{2}\omega $
For part AO ; $ e _{OA}=e _{O}-e _{A}=\frac{1}{2}Bl^{2}\omega $
For part OC; $ e _{OC}=e _{O}-e _{C}=\frac{1}{2}B{{(3l)}^{2}}\omega $
$ \therefore e _{A}-e _{C}=4\ Bl^{2}\omega $
