SATHEE: Electro Magnetic Induction And Alternating Currents Question 328

Electro Magnetic Induction And Alternating Currents Question 328

Question: As a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with $B = 0.15, t e s l a .$ If the resistance is $3, Ω$ , force needed to move the rod as indicated with a constant speed of $2 m / s e c$ is [MP PET 1994]

Options:

A) $3.75 \times 10^{- 3}$ N

B) $3.75 \times 10^{- 2}, N$

C) $3.75 \times 10^{2}, N$

D) $3.75 \times 10^{- 4} N$

Show Answer

Answer:

Correct Answer: A

Solution:

Induced current in the circuit

$i = \frac{B v l}{R}$

Magnetic force acting on the wire $F_{m} = B i l = B (\frac{B v l}{R}) l$

$\Rightarrow F_{m} = \frac{B^{2} v l^{2}}{R}$

External force needed to move the rod with constant velocity

$(F_{m}) = \frac{B^{2} v l^{2}}{R} = \frac{{(0.15)}^{2} \times (2) \times {(0.5)}^{2}}{3}$ $= 3.75 \times 10^{- 3} N$

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Electro Magnetic Induction And Alternating Currents Question 328

Question: As a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with $B = 0.15, t e s l a .$ If the resistance is $3, Ω$ , force needed to move the rod as indicated with a constant speed of $2 m / s e c$ is [MP PET 1994]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electro Magnetic Induction And Alternating Currents Question 328

Question: As a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with B=0.15,tesla. If the resistance is 3,Ω , force needed to move the rod as indicated with a constant speed of 2m/sec is [MP PET 1994]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: As a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with $B = 0.15, t e s l a .$ If the resistance is $3, Ω$ , force needed to move the rod as indicated with a constant speed of $2 m / s e c$ is [MP PET 1994]