Electro Magnetic Induction And Alternating Currents Question 326

Question: A physicist works in a laboratory where the magnetic field is 2 T. She wears a necklace enclosing area 0.01 m2 in such a way that the plane of the necklace is normal to the field and is having a resistance R = 0.01 W. Because of power failure, the field decays to 1 T in time 10?3 seconds. Then what is the total heat produced in her necklace ? (T = Tesla) [Orissa JEE 2002]

Options:

A) 10 J

B) 20 J

C) 30 J

D) 40 J

Show Answer

Answer:

Correct Answer: A

Solution:

$ H=\frac{V^{2}t}{R},and $

$ V=\frac{N(B_{2}-B_{1})A\cos \theta }{t} $

$ V=\frac{1\times (1-2)\times 0.01\times \cos 0^{o}}{{{10}^{-3}}}=10\ V $

So, $ H=\frac{{{(10)}^{2}}\times {{10}^{-3}}}{0.01}=10\ J $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक