SATHEE: Electro Magnetic Induction And Alternating Currents Question 319

Electro Magnetic Induction And Alternating Currents Question 319

Question: A coil of wire having finite inductance and resistance has a conducting ring placed coaxially within it. The coil is connected to a battery at time t = 0, so that a time-dependent current $I_{1} (t)$ starts flowing through the coil. If $I_{2} (t)$ is the current induced in the ring. and $B (t)$ is the magnetic field at the axis of the coil due to $I_{1} (t),$ then as a function of time (t > 0), the product I2 (t) B(t) [IIT-JEE (Screening) 2000]

Options:

A) Increases with time

B) Decreases with time

C) Does not vary with time

D) Passes through a maximum

Show Answer

Answer:

Correct Answer: D

Solution:

Using k1, k2 etc, as different constants.

$I_{1} (t) = k_{1} [1 - e^{- t / τ}], B (t) = k_{2} I_{1} (t)$
$I_{2} (t) = k_{3} \frac{d B (t)}{d t} = k_{4} e^{- t / τ}$

$∴ I_{2} (t) B (t) = k_{5} [1 - e^{- t / τ}] [e^{- t / τ}]$
This quantity is zero for $t = 0$ and $t = \infty$ and positive for other value of t. It must, therefore, pass through a maximum.

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Electro Magnetic Induction And Alternating Currents Question 319

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

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एनसीईआरटी व्यायाम वीडियो समाधान

Electro Magnetic Induction And Alternating Currents Question 319

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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