SATHEE: Electro Magnetic Induction And Alternating Currents Question 317

Electro Magnetic Induction And Alternating Currents Question 317

Question: A wire of length 1 m is moving at a speed of 2ms?1 perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 6 W. The rate at which work is being done to keep the wire moving at constant speed is [Roorkee 1999]

Options:

A) $\frac{1}{12} W$

B) $\frac{1}{6} W$

C) $\frac{1}{3} W$

D) 1W

Show Answer

Answer:

Correct Answer: B

Solution:

Rate of work $= \frac{W}{t} = P = F v;$
also $F = B i l = B, (\frac{B v l}{R}) l$

Þ $P = \frac{B^{2} v^{2} l^{2}}{R} = \frac{{(0.5)}^{2} \times {(2)}^{2} \times {(1)}^{2}}{6} = \frac{1}{6} W$

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Electro Magnetic Induction And Alternating Currents Question 317

Question: A wire of length 1 m is moving at a speed of 2ms?1 perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 6 W. The rate at which work is being done to keep the wire moving at constant speed is [Roorkee 1999]

Options:

Answer:

Solution:

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