Electro Magnetic Induction And Alternating Currents Question 275

Question: In a region of uniform magnetic induction $ B={{10}^{-2}},tesla $ , a circular coil of radius 30 cm and resistance p2 ohm is rotated about an axis which is perpendicular to the direction of B and which forms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating current induced in the coil is [CBSE PMT 1990]

Options:

A) 4p2 mA

B) 30 mA

C) 6 mA

D) 200 mA

Show Answer

Answer:

Correct Answer: C

Solution:

Amplitude of the current $ i_{0}=\frac{e_{0}}{R}=\frac{\omega NBA}{R}=\frac{2\pi \nu NB(\pi r^{2})}{R} $ $ i_{0}=\frac{2\pi \times 1\times {{10}^{-2}}\times \pi {{(0.3)}^{2}}}{{{\pi }^{2}}}=6\times {{10}^{-3}}A=6mA $



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