Electro Magnetic Induction And Alternating Currents Question 255
Question: A power transformer is used to step up an alternating e.m.f. of 220 V to 11 kV to transmit 4.4 kW of power. If the primary coil has 1000 turns, what is the current rating of the secondary ? Assume 100% efficiency for the transformer [MP PET 1997]
Options:
A) 4 A
B) 0.4 A
C) 0.04 A
D) 0.2 A
Show Answer
Answer:
Correct Answer: B
Solution:
$ i_{s}=\frac{P_{s}}{V_{s}}=\frac{4.4\times 10^{3}}{11\times 10^{3}}=0.4\ A $
