Electro Magnetic Induction And Alternating Currents Question 255

Question: A power transformer is used to step up an alternating e.m.f. of 220 V to 11 kV to transmit 4.4 kW of power. If the primary coil has 1000 turns, what is the current rating of the secondary ? Assume 100% efficiency for the transformer [MP PET 1997]

Options:

A) 4 A

B) 0.4 A

C) 0.04 A

D) 0.2 A

Show Answer

Answer:

Correct Answer: B

Solution:

$ i_{s}=\frac{P_{s}}{V_{s}}=\frac{4.4\times 10^{3}}{11\times 10^{3}}=0.4\ A $



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