Electro Magnetic Induction And Alternating Currents Question 247

Question: A loss free transformer has 500 turns on its primary winding and 2500 in secondary. The meters of the secondary indicate 200 volts at 8 amperes under these conditions. The voltage and current in the primary is [MP PMT 1996]

Options:

A) 100 V, 16 A

B) 40 V, 40 A

C) 160 V, 10 A

D) 80 V, 20 A

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{V_{p}}{V_{s}}=\frac{N_{p}}{N_{s}}=\frac{500}{2500}=\frac{1}{5}\Rightarrow V_{p}=\frac{200}{5}=40\ V $

Also $ i_{p}V_{p}=i_{s}V_{s}\Rightarrow i_{p}=i_{s}\frac{V_{s}}{V_{p}}=8\times 5=40\ A $



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