Electro Magnetic Induction And Alternating Currents Question 187

Question: A capacitor of 10μF and an inductor of 1 H are joined in series. An ac of 50 Hz is applied to this combination. What is the impedance of the combination?

Options:

A) 5(π25)πΩ

B) 102(10π2)πΩ

C) 10(π25)πΩ

D) 52(10π2)πΩ

Show Answer

Answer:

Correct Answer: B

Solution:

  • Here, XL=ωL=2πfL=2π×50×1=100πΩ

    Xc=1ωC=12πfC=12π×50×10×106=103πΩ

    So, =|XL.XC|.=|100π.103π|.=|102.[π210π]|.Ω



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