Electro Magnetic Induction And Alternating Currents Question 176

Question: A condenser of capacity C is charged to a potential difference of V1 . The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to V2 is

Options:

A) (C(V12V22)L)1/2

B) (C(V1V2)2L)1/2

C) C(V12V22)L

D) C(V1V2)L

Show Answer

Answer:

Correct Answer: A

Solution:

  • q=CV1cosωti=dqdt=ωCv1sinωt

    Also, ω2=1LC

    and V=V1cosωt At t=t1 ,

    V=V2

    and i=ωCV1sinωt1

    cosωt1=V2V1

    (-ve sign gives direction) Hence, i=V1CL(1V22V12)1/2=(C(V12V22L)1/2



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