SATHEE: Electro Magnetic Induction And Alternating Currents Question 16

Electro Magnetic Induction And Alternating Currents Question 16

Question: An alternating voltage $E = 200 \sqrt{2} \sin (100, t)$ is connected to a 1 microfarad capacitor through an ac ammeter. The reading of the ammeter shall be [NCERT 1984; MNR 1995; MP PET 1999; RPET 1999; UPSEAT 2000]

Options:

A) 10 mA

B) 20 mA

C) 40 mA

D) 80 mA

Show Answer

Answer:

Correct Answer: B

Solution:

Reading of ammeter $= i_{r m s} = \frac{V_{r m s}}{X_{C}} = \frac{V_{0} ω C}{\sqrt{2}}$ $= \frac{200 \sqrt{2} \times 100 \times (1 \times 10^{- 6})}{\sqrt{2}} = 2 \times 10^{- 2} A = 20 m A$

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Electro Magnetic Induction And Alternating Currents Question 16

Question: An alternating voltage E=2002sin⁡(100,t) is connected to a 1 microfarad capacitor through an ac ammeter. The reading of the ammeter shall be [NCERT 1984; MNR 1995; MP PET 1999; RPET 1999; UPSEAT 2000]

Options:

Answer:

Solution:

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Question: An alternating voltage $E = 200 \sqrt{2} \sin (100, t)$ is connected to a 1 microfarad capacitor through an ac ammeter. The reading of the ammeter shall be [NCERT 1984; MNR 1995; MP PET 1999; RPET 1999; UPSEAT 2000]