Electro Magnetic Induction And Alternating Currents Question 16

Question: An alternating voltage $ E=200\sqrt{2}\sin (100,t) $ is connected to a 1 microfarad capacitor through an ac ammeter. The reading of the ammeter shall be [NCERT 1984; MNR 1995; MP PET 1999; RPET 1999; UPSEAT 2000]

Options:

A) 10 mA

B) 20 mA

C) 40 mA

D) 80 mA

Show Answer

Answer:

Correct Answer: B

Solution:

Reading of ammeter $ =i_{rms}=\frac{V_{rms}}{X_{C}}=\frac{V_{0}\omega C}{\sqrt{2}} $ $ =\frac{200\sqrt{2}\times 100\times (1\times {{10}^{-6}})}{\sqrt{2}}=2\times {{10}^{-2}}A=20\ mA $



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