Electro Magnetic Induction And Alternating Currents Question 159
Question: If $ i_{1}=3,\sin ,\omega t $ and $ i_{2}=4,\cos ,\omega t $ , then $ i_{3} $ is
Options:
A) $ 5,\sin ,(\omega t+53^{o}) $
B) $ 5,\sin ,(\omega t+37^{o}) $
C) $ 5,\sin ,(\omega t+45^{o}) $
D) $ 5,\cos ,(\omega t+53^{o}) $
Show Answer
Answer:
Correct Answer: A
Solution:
-
$ i_{3}=i_{1}+i_{2}=3,\sin ,\omega t+4,\cos ,\omega t $
$ =5\sin ,(\omega t+\phi ) $ ,
where $ \tan \phi =\frac{3}{4} $ or $ \phi =53^{o} $
