Electro Magnetic Induction And Alternating Currents Question 136
Question: The voltage of an ac source varies with time according to the equation $ V=100\sin \ 100\pi t\cos 100\pi t $ where $ t $ is in seconds and V is in volts. Then [MP PMT 1996; 2000]
Options:
A) The peak voltage of the source is 100 volts
B) The peak voltage of the source is 50 volts
C) The peak voltage of the source is $ 100/\sqrt{2} $ volts
D) The frequency of the source is 50 Hz
Show Answer
Answer:
Correct Answer: B
Solution:
$ V=50\times 2,\sin ,100\pi t,\cos ,100\pi t=50\sin 200\pi t $
$ \Rightarrow V_{0}=50,Volts $ and $ \nu =100Hz $