SATHEE: Electro Magnetic Induction And Alternating Currents Question 130

Electro Magnetic Induction And Alternating Currents Question 130

Question: In an LR-circuit, the inductive reactance is equal to the resistance R of the circuit. An e.m.f. $E = E_{0} \cos (ω t)$ applied to the circuit. The power consumed in the circuit is [MP PMT 1997]

Options:

A) $\frac{E_{0}^{2}}{R}$

B) $\frac{E_{0}^{2}}{2 R}$

C) $\frac{E_{0}^{2}}{4 R}$

D) $\frac{E_{0}^{2}}{8 R}$

Show Answer

Answer:

Correct Answer: C

Solution:

$P = E_{r m s} i_{r m s} \cos φ = \frac{E_{0}}{\sqrt{2}} \times \frac{i_{0}}{\sqrt{2}} \times \frac{R}{Z}$

Þ $\frac{E_{0}}{\sqrt{2}} \times \frac{E_{0}}{Z \sqrt{2}} \times \frac{R}{Z}$

$\Rightarrow P = \frac{E_{0}^{2} R}{2 Z^{2}}$ Given $X_{L} = R$ so, $Z = \sqrt{2} R$

$\Rightarrow, P = \frac{E_{0}^{2}}{4 R}$

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Electro Magnetic Induction And Alternating Currents Question 130

Question: In an LR-circuit, the inductive reactance is equal to the resistance R of the circuit. An e.m.f. $E = E_{0} \cos (ω t)$ applied to the circuit. The power consumed in the circuit is [MP PMT 1997]

Options:

Answer:

Solution:

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Electro Magnetic Induction And Alternating Currents Question 130

Question: In an LR-circuit, the inductive reactance is equal to the resistance R of the circuit. An e.m.f. E=E0cos⁡(ωt) applied to the circuit. The power consumed in the circuit is [MP PMT 1997]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: In an LR-circuit, the inductive reactance is equal to the resistance R of the circuit. An e.m.f. $E = E_{0} \cos (ω t)$ applied to the circuit. The power consumed in the circuit is [MP PMT 1997]