SATHEE: Atoms And Nuclei Question 86

Atoms And Nuclei Question 86

Question: When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: $h = 6.6 \times 10^{- 34} J -s$ ) [AFMC 2000; Pb. PET 2001]

Options:

A) $4.16 \times 10^{- 34}, J - s$

B) $3.32 \times 10^{- 34}, J - s$

C) $1.05 \times 10^{- 34}, J - s$

D) $2.08 \times 10^{- 34}, J - s$

Show Answer

Answer:

Correct Answer: C

Solution:

Change in the angular momentum $Δ L = L_{2} - L_{1} = \frac{n_{2} h}{2 π} - \frac{n_{1} h}{2 π}$
$\Rightarrow Δ L = \frac{h}{2 π} (n_{2} - n_{1})$ $= \frac{6.6 \times 10^{- 34}}{2 \times 3.14} (5 - 4)$ $= 1.05 \times 10^{- 34} J - S$

पिछला

अगला

Atoms And Nuclei Question 86

Question: When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: $h = 6.6 \times 10^{- 34} J -s$ ) [AFMC 2000; Pb. PET 2001]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Atoms And Nuclei Question 86

Question: When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: h=6.6×10−34J-s ) [AFMC 2000; Pb. PET 2001]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

Question: When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: $h = 6.6 \times 10^{- 34} J -s$ ) [AFMC 2000; Pb. PET 2001]