SATHEE: Atoms And Nuclei Question 85

Atoms And Nuclei Question 85

Question: If scattering particles are 56 for $90^{o}$ angle then this will be at $60^{o}$ angle [RPMT 2000]

Options:

A) 224

B) 256

C) 98

D) 108

Show Answer

Answer:

Correct Answer: A

Solution:

According to scattering formula $N \propto \frac{1}{\sin^{4} (θ / 2)} \Rightarrow \frac{N_{2}}{N_{1}} = {[\frac{\sin (θ_{1} / 2)}{\sin (θ_{2} / 2)}]}^{4}$
$\Rightarrow \frac{N_{2}}{N_{1}} = {[\frac{\sin \frac{90^{o}}{2}}{\sin \frac{60^{o}}{2}}]}^{4} = {[\frac{\sin 45^{o}}{\sin 30^{o}}]}^{4}$
$\Rightarrow N_{2} = {(\sqrt{2})}^{4} \times N_{1} = 4 \times 56 = 224$

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Atoms And Nuclei Question 85

Question: If scattering particles are 56 for 90o angle then this will be at 60o angle [RPMT 2000]

Options:

Answer:

Solution:

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Question: If scattering particles are 56 for $90^{o}$ angle then this will be at $60^{o}$ angle [RPMT 2000]