Atoms And Nuclei Question 85

Question: If scattering particles are 56 for $ 90^{o} $ angle then this will be at $ 60^{o} $ angle [RPMT 2000]

Options:

A) 224

B) 256

C) 98

D) 108

Show Answer

Answer:

Correct Answer: A

Solution:

According to scattering formula $ N\propto \frac{1}{{{\sin }^{4}}(\theta /2)}\Rightarrow \frac{N_{2}}{N_{1}}={{[ \frac{\sin ({\theta_{1}}/2)}{\sin ({\theta_{2}}/2)} ]}^{4}} $
$ \Rightarrow \frac{N_{2}}{N_{1}}={{[ \frac{\sin \frac{90^{o}}{2}}{\sin \frac{60^{o}}{2}} ]}^{4}}={{[ \frac{\sin 45^{o}}{\sin 30^{o}} ]}^{4}} $
$ \Rightarrow N_{2}={{(\sqrt{2})}^{4}}\times N_{1}=4\times 56=224 $



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