Atoms And Nuclei Question 445

Question: If $ {\lambda_{\max }} $ is 6563 $ \overset{o}{\mathop{A}}, $ , then wave length of second line for Balmer series will be

Options:

A) $ \lambda =\frac{16}{3R} $

B) $ \lambda =\frac{36}{5R} $

C) $ \lambda =\frac{4}{3R} $

D) None of the above

Show Answer

Answer:

Correct Answer: A

Solution:

  • For Balmer series $ \frac{1}{\lambda }=R( \frac{1}{2^{2}}-\frac{1}{n^{2}} ) $

$ \frac{1}{\lambda }=R\frac{1}{2^{2}}-\frac{1}{4^{2}} $ where n = 3, 4, 5 For second line n = 4

So $ \frac{1}{\lambda }=R( \frac{1}{2^{2}}-\frac{1}{4^{2}} )$

=$\frac{3}{16}R\Rightarrow \lambda =\frac{16}{3R} $



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