Atoms And Nuclei Question 42

Question: The ratio of the frequencies of the long wavelength limits of Lyman and Balmer series of hydrogen spectrum is [KCEE 1996]

Options:

A) 27 : 5

B) 5 : 27

C) 4 : 1

D) 1 : 4

Show Answer

Answer:

Correct Answer: A

Solution:

For Lyman series
$ {\nu_{Lymen}}=\frac{c}{{\lambda_{\max }}}=Rc[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} ]=\frac{3RC}{4} $
For Balmer series
$ {\nu_{Balmer}}=\frac{c}{{\lambda_{\max }}}=Rc[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(3)}^{2}}} ]=\frac{5RC}{36} $ \ $ \frac{{\nu_{Lymen}}}{{\nu_{Balmer}}}=\frac{27}{5} $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक