Atoms And Nuclei Question 380

Question: The half-life of radioactive Radon is 3.8 days. The time at the end of which $ \frac{1}{20} $ th of the radon sample will remain undecayed is $ ( \text{given lo}{{g}_{e}}=0.4343 ) $

Options:

A) 3.8 days

B) 16.5 days

C) 33 days

D) 76 days.

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ {t_{1/2}}=3.8 $ day
    $ \therefore \lambda =\frac{0.693}{{t_{1/2}}}=\frac{0.693}{3.8}=0.182 $

If the initial number of atom is $ a=A_{0} $ then after time t the number of atoms is $ a/20=A $ .

We have to find t. $ t=\frac{2.303}{\lambda }\log \frac{A_{0}}{A}=\frac{2.303}{0.182}\log \frac{a}{a/20} $ $ =\frac{2.303}{0.182}\log 20=16.46 $ days



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