SATHEE: Atoms And Nuclei Question 380

Atoms And Nuclei Question 380

Question: The half-life of radioactive Radon is 3.8 days. The time at the end of which $\frac{1}{20}$ th of the radon sample will remain undecayed is $(given lo g_{e} = 0.4343)$

Options:

A) 3.8 days

B) 16.5 days

C) 33 days

D) 76 days.

Show Answer

Answer:

Correct Answer: B

Solution:

$t_{1 / 2} = 3.8$ day
$∴ λ = \frac{0.693}{t_{1 / 2}} = \frac{0.693}{3.8} = 0.182$

If the initial number of atom is $a = A_{0}$ then after time t the number of atoms is $a / 20 = A$ .

We have to find t. $t = \frac{2.303}{λ} \log \frac{A_{0}}{A} = \frac{2.303}{0.182} \log \frac{a}{a / 20}$ $= \frac{2.303}{0.182} \log 20 = 16.46$ days

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Atoms And Nuclei Question 380

Question: The half-life of radioactive Radon is 3.8 days. The time at the end of which 120 th of the radon sample will remain undecayed is (given loge=0.4343)

Options:

Answer:

Solution:

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Question: The half-life of radioactive Radon is 3.8 days. The time at the end of which $\frac{1}{20}$ th of the radon sample will remain undecayed is $(given lo g_{e} = 0.4343)$