Atoms And Nuclei Question 355
Question: If 200 MeV energy is released in the fission of a single $ U^{235} $ nucleus, the number of fissions required per second to produce 1 kilowatt power shall be(Given $ ,1eV=1.6\times {{10}^{-19}}J $ )
Options:
A) $ 3.125\times 10^{13} $
B) $ ,3.125\times 10^{14} $
C) $ 3.125\times 10^{15} $
D) $ 3.125\times 10^{16} $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ P-n( \frac{E}{t} )\Rightarrow 1000=\frac{n\times 200\times 10^{6}\times 1.6\times {{10}^{-19}}}{t} $
$ \Rightarrow ,\frac{n}{t}=3.125\times 10^{13}. $
