SATHEE: Atoms And Nuclei Question 350

Atoms And Nuclei Question 350

Question: Determine the power output of a $_{92} U^{235}$ reactor if it takes 30 days to use 2kg of fuel. Energy released per fission is 200 MeV and $N = 6.023 \times 10^{26}$ per kilo mole.

Options:

A) 63.28 MW

B) 3.28 MW

C) 0.6 MW

D) 50.12 MW

Show Answer

Answer:

Correct Answer: A

Solution:

Number of atoms in 2kg fuel

$= \frac{2}{235} \times 6.023 \times 10^{26} = 5.12 \times 10^{24}$

number of fission per second

$= \frac{5.12 \times 10^{24}}{30 \times 24 \times 60 \times 60} = 1.978 \times 10^{18}$ Energy released per fission $= 200, M e V = 200 \times 1.6 \times 10^{- 13} = 3.2 \times 10^{- 11} J$

Power output $= 3.2 \times 10^{- 11} \times 1.978 \times 10^{18}$

$= 63.28 \times 10^{6} W = 63.28, M W$

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Atoms And Nuclei Question 350

Question: Determine the power output of a 92U235 reactor if it takes 30 days to use 2kg of fuel. Energy released per fission is 200 MeV and N=6.023×1026 per kilo mole.

Options:

Answer:

Solution:

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Question: Determine the power output of a $_{92} U^{235}$ reactor if it takes 30 days to use 2kg of fuel. Energy released per fission is 200 MeV and $N = 6.023 \times 10^{26}$ per kilo mole.