Atoms And Nuclei Question 346
Question: Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron=1. 1 MeV and for helium=7.0 MeV)
Options:
A) 30.2 MeV
B) 32.4 MeV
C) 23.6 MeV
D) 25.8 MeV
Show Answer
Answer:
Correct Answer: C
Solution:
-
$ _{1}H^{2}+ _{1}H^{2}\to _{2}He^{4} $
Total binding energy of two deuterium nuclei $ =1.1\times 4=4.4,MeV $ Binding energy of a $ _{2}He^{4} $
nuclei $ =4\times 7=28MeV $
Energy released in this process $ =28-4.4=23.6MeV $
