Atoms And Nuclei Question 330

Question: If the nuclear radius of $ ^{27}Al $ is 3.6 Fermi, the approximate nuclear radius of $ ^{64}Cu $ in Fermi is

Options:

A) 4.8

B) 3.6

C) 2.4

D) 1.2

Show Answer

Answer:

Correct Answer: A

Solution:

  • Nuclear radius, $ r\propto {{A}^{1/3}} $ where A is mass number $ \frac{r_{Cu}}{r_{Al}}={{( \frac{A_{Cu}}{A_{Al}} )}^{1/3}}={{( \frac{64}{27} )}^{1/3}} $
    $ \Rightarrow r_{Cu}=3.6( \frac{4}{3} )=4.8,Fermi $


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