Atoms And Nuclei Question 321

Question: If the wavelength of the first line of the Balmer series in the hydrogen spectrum is K, then the wavelength of the first line of the Lyman series is

Options:

A) (27/5)λ

B) (5/27)λ

C) (32/27)λ

D) (27/32)λ

Show Answer

Answer:

Correct Answer: B

Solution:

  • For first line of Balmer series 1λ=R(1419)R=365λ
    Wavelength of the first line, λL of the Lyman series is given by 1λL=R(114)=365λ×34=275λ
    λL=5λ27


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