Atoms And Nuclei Question 3

Question: In the nth orbit, the energy of an electron $ E_{n}=-\frac{13.6}{n^{2}}eV $ for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be [MP PMT 1987; CPMT 1991, 97; RPMT 1999; DCE 2001; Kerala PMT 2004]

Options:

A) $ 10.2\ eV $

B) $ 12.1\ eV $

C) $ 13.6\ eV $

D) $ 3.4\ eV $

Show Answer

Answer:

Correct Answer: A

Solution:

$ {E_{1\to 2}}=-3.4-(13.6)=+10.2,eV $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक