Atoms And Nuclei Question 267
Question: Excitation energy of a hydrogen like ion in its excitation state is 40.8 eV. Energy needed to remove the electron from the ion in ground state is
Options:
A) 54.4 eV
B) 13.6eV
C) 40.8 eV
D) 27.2 eV
Show Answer
Answer:
Correct Answer: A
Solution:
- Excitation energy $ \Delta E=E_{2}-E_{1}=13.6Z^{2} $
$ [ \frac{1}{1^{2}}-\frac{1}{2^{2}} ] $
$ \Rightarrow 40.8=13.6\times \frac{3}{4}\times Z^{2}\Rightarrow ,=2. $
Now required energy to remove the electron from ground state $ =\frac{+13.6Z^{2}}{{{( 1 )}^{2}}}=13.6{{( Z )}^{2}}=54.4eV. $
