Atoms And Nuclei Question 239

Question: The binding energy per nucleon of deuterium and helium atom is 1.1 MeV and 7.0 MeV. If two deuterium nuclei fuse to form helium atom, the energy released is [Pb. PMT 2001; CPMT 2001; AIEEE 2004]

Options:

A) 19.2 MeV

B) 23.6 MeV

C) 26.9 MeV

D) 13.9 MeV

Show Answer

Answer:

Correct Answer: B

Solution:

1H2+1H22He4+ energy

Binding energy of a 1H2 deuterium nuclei '

=2×1.1=2.2 MeV '

Total binding energy of two deuterium nuclei =2.2×2=4.4 MeV B'

inding energy of a 2He4 nuclei =4×7=28 MeV '

So, energy released in fusion =284.4=23.6 MeV



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