Atoms And Nuclei Question 234

Question: Energy released in fusion of 1 kg of deuterium nuclei [RPET 2000]

Options:

A) 8×1013,J

B) 6×1027,J

C) 2×107,KwH

D) 8×1023,MeV

Show Answer

Answer:

Correct Answer: D

Solution:

Fusion reaction of deuterium is 1H2+1H22He3+0n1+3.27 MeV So E=6.02×1023×103×3.27×1.6×10132×2 =7.8×1013J =8×1013J .



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